Step 2: On the Query tab add the following code and run it CREATE DATABASE IF NOT EXISTS bug_test_db CHARACTER SET = 'latin1' COLLATE = 'latin1_general_ci'; USE bug_test_db; CREATE TABLE IF NOT EXISTS ...
Hello all! I have a MySQL query that is giving me the results that I want, but I'm having difficulty displaying the results in PHP. Here is my SQL statement: SELECT `tkid`,COUNT(*) FROM ...
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